6w^2=11w+35

Solution for 6w^2=11w+35 equation:

6w^2=11w+35

We move all terms to the left:

6w^2-(11w+35)=0

We get rid of parentheses

6w^2-11w-35=0

a = 6; b = -11; c = -35;
Δ = b2-4ac
Δ = -112-4·6·(-35)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-31}{2*6}=\frac{-20}{12}
=-1+2/3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+31}{2*6}=\frac{42}{12}
=3+1/2
$